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Inverse Trigonometric Functions · Question 44 of 120

Question 44

EasyOriginal question

Which of these angles is a value of tan⁡−1x\tan^{-1} x for some real xx?

Options for question 44

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. tan⁡−1x\tan^{-1} x takes exactly the values in the open interval (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right).

  2. Only 2π5\frac{2\pi}{5} is inside, since 2π5<π2\frac{2\pi}{5} < \frac{\pi}{2}: it is tan⁡−1(tan⁡2π5)\tan^{-1}\left(\tan \frac{2\pi}{5}\right).

Worth noting

π2\frac{\pi}{2} is an end of the branch, which the open interval leaves out: tan⁡π2\tan \frac{\pi}{2} is not defined.

Concept
Where a principal value lies
Typical time
60 s
Your time
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The rule this testsPrincipal values
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.