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Vectors · Question 88 of 125

Question 88

HardOriginal question

a⃗\vec{a} and b⃗\vec{b} are unit vectors at an angle θ\theta. What is ∣a⃗−b⃗∣\lvert \vec{a} - \vec{b} \rvert?

Options for question 88

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. ∣a⃗−b⃗∣2=1+1−2cos⁡θ=2(1−cos⁡θ)\lvert \vec{a} - \vec{b} \rvert^{2} = 1 + 1 - 2\cos \theta = 2(1 - \cos \theta).

  2. 1−cos⁡θ=2sin⁡2θ21 - \cos \theta = 2\sin^{2}\frac{\theta}{2}, so ∣a⃗−b⃗∣=2sin⁡θ2\lvert \vec{a} - \vec{b} \rvert = 2\sin\frac{\theta}{2}, which is not negative since θ2\frac{\theta}{2} lies in [0,π2]\left[0, \frac{\pi}{2}\right].

Worth noting

2cos⁡θ22\cos\frac{\theta}{2} is ∣a⃗+b⃗∣\lvert \vec{a} + \vec{b} \rvert, where 2cos⁡θ2\cos \theta is added, not taken away.

Concept
The difference of two unit vectors
Typical time
120 s
Your time
—
The rule this testsThe scalar product
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Ten questions from Vectors, at your own pace.

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Ten questions from Vectors, at your own pace.