The two equal sides of an isosceles triangle are 25 cm each and the third side is 14 cm. What is its area?

Explanation

1. 01

   The height to the 14 cm side bisects it into 7 cm and 7 cm.

2. 02

   Height = $\sqrt{25^2 - 7^2} = \sqrt{576} = 24$ cm.

3. 03

   Area = $\frac{1}{2} \times 14 \times 24 = 168$ cm².