A hemispherical bowl has an inner radius of 21 cm. How much can it hold, in cubic centimetres? Take $\pi = \frac{22}{7}$ .

2,772 cm³Correct answerYour answer9,702 cm³Correct answerYour answer19,404 cm³Correct answerYour answer38,808 cm³Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Volume of a hemisphere = $\frac{2}{3}\pi r^3$ .
= $\frac{2}{3} \times \frac{22}{7} \times 21 \times 21 \times 21 = 19{,}404$ cm³.

Worth noting

38,808 cm³ is a full sphere. A hemisphere is half of it.

Ten questions from Mensuration: Areas and Volumes, at your own pace.

Ten questions from Mensuration: Areas and Volumes, at your own pace.

A hemispherical bowl has an inner radius of 21 cm. How much can it hold, in cubic centimetres? Take π=227\pi = \frac{22}{7}π=722​.