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Area of Bounded Regions · Question 26 of 115

The line x = 2 cuts R into two parts.

Question 26

HardOriginal question

A region RR lies in the first quadrant. It is bounded by the yy-axis, the lines y=1y = 1 and y=4y = 4, and the line x+y=6x + y = 6.

The line x=2x = 2 cuts RR into two parts. What is the area of the part to the right of x=2x = 2?

Options for question 26

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. For 1≤y≤41 \le y \le 4, 6−y≥26 - y \ge 2, so every strip of RR crosses x=2x = 2; the part to the right has strips of length 4−y4 - y.

  2. ∫14(4−y) dy=[4y−y22]14=8−72=92\int_1^{4} (4 - y)\,dy = \left[4y - \frac{y^{2}}{2}\right]_1^{4} = 8 - \frac{7}{2} = \frac{9}{2} square units, which is 212−6\frac{21}{2} - 6.

Worth noting

6 is the part to the left of x=2x = 2, the rectangle 2×32 \times 3.

Concept
A part from the whole
Typical time
150 s
Your time
—
The rule this testsRegions with lines
Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.

Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.