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Conditional Probability & Bayes' Theorem · Question 20 of 125

What is P(F E)?

Question 20

MediumOriginal question

Two fair dice are thrown. EE: the sum is 9. FF: at least one die shows a 5.

What is P(F∣E)P(F \mid E)?

Options for question 20

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Given EE, only its 4 outcomes remain.

  2. Two of them, (4,5)(4, 5) and (5,4)(5, 4), show a 5: 24=12\frac{2}{4} = \frac{1}{2}.

Worth noting

211\frac{2}{11} is P(E∣F)P(E \mid F), the condition the other way round.

Concept
Conditional probability by counting
Typical time
120 s
Your time
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The rule this testsConditional probability
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.