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Continuity & Differentiability · Question 77 of 125

Question 77

HardOriginal question

At how many points is f(x)={x+1,x<0x2,0≤x<22x,x≥2f(x) = \begin{cases} x + 1, & x < 0 \\ x^{2}, & 0 \le x < 2 \\ 2x, & x \ge 2 \end{cases} not continuous?

Options for question 77

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Each piece is a polynomial, so only the joins at 0 and 2 can break.

  2. At 0: 0+1=10 + 1 = 1 on the left, 02=00^{2} = 0 on the right, a break. At 2: 22=4=2×22^{2} = 4 = 2 \times 2, no break. So 1 point.

Worth noting

2 assumes every join is a break; at x=2x = 2 the pieces meet.

Concept
Counting the breaks in a piecewise function
Typical time
120 s
Your time
—
The rule this testsContinuous functions
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Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.