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Increasing & Decreasing Functions · Question 62 of 74

Question 62

HardOriginal question

Within (0,π)(0, \pi), on which interval is f(x)=sin⁡x+cos⁡xf(x) = \sin x + \cos x strictly increasing?

Options for question 62

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. f′(x)=cos⁡x−sin⁡xf'(x) = \cos x - \sin x, which is 0 where tan⁡x=1\tan x = 1: x=π4x = \frac{\pi}{4}.

  2. For 0<x<π40 < x < \frac{\pi}{4}, cos⁡x>sin⁡x\cos x > \sin x, so f′>0f' > 0; after π4\frac{\pi}{4}, f′<0f' < 0.

Worth noting

(0,π2)\left(0, \frac{\pi}{2}\right) runs past the peak at π4\frac{\pi}{4}, after which ff falls.

Concept
A sum of sine and cosine
Typical time
120 s
Your time
—
The rule this testsTrigonometric functions
Practise this chapter →

Ten questions from Increasing & Decreasing Functions, at your own pace.

Practise this chapter →

Ten questions from Increasing & Decreasing Functions, at your own pace.