What is the shortest distance between the lines (x - 2)/1 = (y + 1)/2 = (z - 4)/3 and (x - 2)/3 = (y + 1)/(-1) = (z - 4)/2?

Three-Dimensional Geometry · Question 88 of 120

Question 88

EasyOriginal question

What is the shortest distance between the lines $\frac{x - 2}{1} = \frac{y + 1}{2} = \frac{z - 4}{3}$ and $\frac{x - 2}{3} = \frac{y + 1}{-1} = \frac{z - 4}{2}$ ?

0

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1

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\sqrt{14}

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7 \sqrt{3}

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Show the answer and explanation

CorrectNot quiteAnswer A

Correct answer: A

Worth noting

$\sqrt{14}$ is the distance between $(1, 2, 3)$ and $(3, -1, 2)$ , the denominators read as points.

Ten questions from Three-Dimensional Geometry, at your own pace.

Ten questions from Three-Dimensional Geometry, at your own pace.