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Vectors · Question 111 of 125

Question 111

MediumOriginal question

a⃗=i^−j^+2k^\vec{a} = \hat{i} - \hat{j} + 2\hat{k} and b⃗=2i^+j^−k^\vec{b} = 2\hat{i} + \hat{j} - \hat{k}. Which of the following statements are true?

I. a⃗×b⃗=−i^+5j^+3k^\vec{a} \times \vec{b} = -\hat{i} + 5\hat{j} + 3\hat{k}.

II. b⃗×a⃗=i^−5j^−3k^\vec{b} \times \vec{a} = \hat{i} - 5\hat{j} - 3\hat{k}.

III. The triangle with sides a⃗\vec{a} and b⃗\vec{b} has area 352\frac{\sqrt{35}}{2}.

IV. ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣\lvert \vec{a} \times \vec{b} \rvert = \lvert \vec{a} \rvert \lvert \vec{b} \rvert.

Options for question 111

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. a⃗×b⃗=i^((−1)(−1)−2(1))−j^(1(−1)−2(2))+k^(1(1)−(−1)(2))=−i^+5j^+3k^\vec{a} \times \vec{b} = \hat{i}((-1)(-1) - 2(1)) - \hat{j}(1(-1) - 2(2)) + \hat{k}(1(1) - (-1)(2)) = -\hat{i} + 5\hat{j} + 3\hat{k}: I is true, and II, its negative, is true too.

  2. III: 121+25+9=352\frac{1}{2}\sqrt{1 + 25 + 9} = \frac{\sqrt{35}}{2}, true. IV: ∣a⃗∣∣b⃗∣=66=6≠35\lvert \vec{a} \rvert \lvert \vec{b} \rvert = \sqrt{6}\sqrt{6} = 6 \ne \sqrt{35}, because a⃗⋅b⃗=−1≠0\vec{a} \cdot \vec{b} = -1 \ne 0; false.

Worth noting

∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣\lvert \vec{a} \times \vec{b} \rvert = \lvert \vec{a} \rvert \lvert \vec{b} \rvert only when the vectors are perpendicular.

Concept
Computing a vector product
Typical time
120 s
Your time
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The rule this testsThe vector product
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Ten questions from Vectors, at your own pace.

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Ten questions from Vectors, at your own pace.